The BSA A7-A10 Forum
Technical (Descriptive Topic Titles - Stay on Topic) => Frame => Topic started by: Andy51 on 31.07. 2016 23:05
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Hi, I am new to this forum. I own an AJS 500 single to which I am fitting a BSA 8 in single sided front brake, a big improvement over the 7 in 7/8 wide original. A work colleague gave me a drawing, from Meridan works, dated 1971, for a new front axle to fit the BSA brake in AMC's Teledraulic forks - the BSA 8 in brake was about the best in the 50s. I bought a brake off flea bay, skimmed the drum, made the axle, and am nearly ready to go. The last piece of the jigsaw is the nut/spacer Required (no dimensions given but 3/4 BSC thread) that holds the alloy brake plate in position and also locates the axle against the left side Teledraulic fork leg - the Teledraulics use separate fork clamping pieces to locate the axle, rather than the threaded end and integral clamp of the BSA arrangement. This in turn dictates the rim offset. I plan to start with the standard (BSA) offset and calculate the nut thickness, work out if a different offset is necessary to get everything to fit with different stanchion spacing, have the wheel built and fine tweak the nut. I have looked on this forum and there appear to be several dimensions given over the years. I am after the offset for a 19 in WM2 rim, as measured with a straightedge across the open edge of the brake drum, to either the rim centre or edge. Can anyone help? Thanking you, Andy
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I started with 17mm (half width hub) and ended dead right centre with that