Triton Thrasher,

I'm sorry, but I have to diasagree, of course you can, provided it is low resistance. After all, that is what the shunt of the ammeter is, i.e. a low value resistor with a meter across it to measure the voltage dropped!

Lets assume that the dynamo has the capability to produce 8 amps of output at full tilt (Probably a little optimistic for an A10, but bear with me!) Most commercially available LED?s operate at 3V(ish)

Using good old Ohms law V/I=R where

V= Volts

I = Current in Amps

R = resistance in Ohms

3/8 = 0.375 of an Ohm. Like I said, a few turns of wire, hardly a ?resistor? I?m sure you will agree? If you are particularly worried about dissipating this much energy , a simple solid state circuit could be constructed. Give me a little time and I'll come up with something...

Phil